In which of the following equations. H2O2 acts as a reducing agent in the acidic medium?
A
H2O2+2H++2e−→2H2O
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B
H2O2+2OH−→2H2O−→2H2O+O2+2e−
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C
H2O2→2H++O2+2e−
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D
H2O2+OH−+2e−→3OH−
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Solution
The correct option is CH2O2→2H++O2+2e− In acidic medium H+ should be there, and in opiton (c) H2O2 loses two electrons and valency of oxygen changes from -1 to 0 , thus acting as a reducing agent .