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Question

In which of the following reaction reactant and products are incorrectly matched?


A
F3CCH=CH2+HClF3CCl|CHCH3
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B
MeCH=CHO||COCH3+IClMeCl|CHI|CHO||COCH3
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C
PhCH=CHCH3HBr−−−ROORPhCH2Br|CHCH3
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D
PhCH=CHCH=CH2HCl−−−ROORPhCl|CHCH=CHCH3
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Solution

The correct option is A F3CCH=CH2+HClF3CCl|CHCH3
A) F3CCH=CH2H+F3CCH2CH2
CF3 being a strong electron withdrawing group will destabilise the secondary carbocation.
 
F3CCH2CH2ClF3CCH2CH2Cl

B) Carbocation next to carbonyl group is unstable, hence I+ attacks that carbon to avoid carbocation formation at that carbon.
C) HBr will  show peroxide effect and benzyl free radical is more stable.
D)HCl will not show peroxide  effect.

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