In which of the following reactions, $H_{2} O_{2}$ acts as reducing agent?

C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}

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H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}

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H C H O + H_{2} O_{2} \to H C O O H + H_{2} O

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P b O_{2} + H_{2} O_{2} \to P b O + H_{2} O + O_{2}

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Solution

The correct options are
A $C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}$
B $H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}$
D $P b O_{2} + H_{2} O_{2} \to P b O + H_{2} O + O_{2}$
A reducing agent will undergo a decrease in oxidation state.
Option A: Oxygen undergoes increase in oxidation state from -1 ( $H_{2} O_{2}$ ) to 0 ( $O_{2}$ ) i.e. oxidation.

Option B: Oxygen undergoes increase in oxidation state from -1 ( $H_{2} O_{2}$ ) to 0 ( $O_{2}$ ) i.e. oxidation.

Option C: Oxygen undergoes decrease in oxidation state from -1 ( $H_{2} O_{2}$ ) to -2 ( $H_{2} O$ ) i.e. reduction.

Option D: Oxygen undergoes increase in oxidation state from -1 ( $H_{2} O_{2}$ ) to 0 ( $O_{2}$ ) i.e. oxidation.

Hence, the correct options are $A$ , $B$ and $D$

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Similar questions

H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}

H_{2} O_{2}

H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}

H_{2} O_{2} + A g_{2} O \to 2 A g + H_{2} O + O_{2}

H_{2} O_{2}

In the reaction $A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2} . H_{2} O_{2}$ acts as :

H_{2} O_{2}

A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2}

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