Question

In $Xe{F}_2$ molecule, the angle between the two lone pair orbitals is $\alpha$, the angle between the lone pair orbital and the bond pair orbital is $\beta$. The angle between the bond pair orbitals $\gamma$ is:

• A. $\alpha =\beta =\gamma$
• B. $\alpha >\beta >\gamma$
• C. $\gamma >\beta >\alpha$
• D. $\gamma >\alpha >\beta$

Answer 1

The correct option is D $\gamma >\alpha >\beta$

$Xe{F}_2$ molecule has two bond pair of electron and 3 lone pairs of electrons. So, it has a hybridisation of $s{p}^{3}d$. The lone pairs occupy the equitorial positions and F atoms occupy the axial positions. Hence, it has an linear shape.


$\alpha$ has an angle of ${120}^o$
$\beta$ has an angle of ${90}^o$
and $\gamma$ has an angle of ${180}^o$