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Question

In young's double slit experiment the two slits are illuminated by light of wavelength 5890 ˙A and it is observed that successive maxima or minima are seperated by angular displacement 2. The whole apparatus is immersed in water, then find out angular fringe width is (μw=43).

A
0.15
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B
0.30
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C
0.5
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D
0.75
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Solution

The correct option is A 0.15
According to question, the angular fringe width in air is :
αair=λad=0.2

Similarly, angular fringe width in water
αwater=λwd

αairαwater=λaλw

αwater=αairλwλa

By snell's law, λaλw=μw

αw=αairμw=0.2(43)
αw=0.15

Hence, option (A) is correct.

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