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Question

Incorrect order about bond angle is:
  1. H2O>H2S>H2Se>H2Te
  2. C2H2>C2H4>CH4>NH3
  3. SF6<NH3<H2O<OF2
  4. ClO2>H2O>H2S>SF6


Solution

The correct option is C SF6<NH3<H2O<OF2
(a) According to VSEPR as electronegativity of central atom decreases, bond angle decreases.
So, bond angle of H2O>H2S>H2Se>H2Te
(b) C2H2sp>C2H4sp2>CH4sp3>NH3sp3
with bond pair - lone pair repulsion,
(c) SF6<NH3<H2O<OF2
In this case, bond angle of NH3 is highest because lp - lp repulsion is minimum in it.
(d) ClO2>H2O>H2S>SF6
ClO2 bond angle is highest due to its sp3 hybridisation, rest all are sp3 or sp3d2 hybridised. more renulsion in double bond electrons.

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