Increase order of electron affinity is

N < O < C l < A l

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O < N < A l < C l

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N < A l < O < C l

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C l < N < O < A l

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Solution

The correct option is C $N < A l < O < C l$
Nitrogen has lowest electron affinity because of half-filled p-orbital which leads to extra stability. While oxygen has lower electron affinity than chlorine beacuse of smaller size and interelectronic repulsion with incoming electron. So correct order $N < A l < O < C l$

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Considering the elements F, Cl, O and N, the correct order of their chemical reactivity in terms of oxidizing property is:

(a) F > Cl > O > N (b) F > O > Cl > N

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