Question

# Indium antimonide has a band gap of 0.23 eV between the valence and the conduction band. Find the temperature at which the thermal energy kT equals the indium antimonide’s band gap. (k=Boltzmann constant,T=temperature) (Take k=1.38×10−23 JK−1)

A
1250 K
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B
1800 K
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C
2670 K
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D
3125 K
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Solution

## The correct option is C 2670 KIt is to be found that the temperature at which the thermal energy kT equals the indium antimonide’s band gap. ∴kT=E ⇒1.38×10−23×T=0.23×1.6×10−19 ⇒T=0.368×10−191.38×10−23 ⇒T=0.2666×104≈2670 K Hence, option (C) is correct.

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