Inert gas has been added to the following equilibrium system at constant volume
$S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g)$
To which direction will the equilibrium shift?

Forward

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Backward

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No effect

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Unpredictable

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Solution

The correct option is C No effect
Since there is no effect on the equilibrium by adding inert gas at constant volume.

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Similar questions

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

; {S O}_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {S O}_{3} (g);

2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

S O_{3 (g)} ⇌ S O_{2 (g)} + \frac{1}{2} O_{2 (g)},

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S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

{S O}_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {S O}_{3} (g)

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