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Question

1sin2xcos2xdx

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Solution

1sin2x.cos2xdxsin2x.cos2x sin2x=2sinx.cosx
=(sinx.cosx)2 12sin2x=sinx.cosx
=(12sin2x)2
=14sin22x
=114sin22xdx
=(14sin22x)1dx
=4cosec22x.dx cosec2x=cotx
=4cot2x×12+c
=2cot2x+c

1177467_1285014_ans_7a070f5b747e4a5b9b547223386a23b7.jpg

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