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Question

x3(1+x2)1/3dx is equal to

A
203(1+x2)23(2x23)+C
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B
320(1+x2)23(2x23)+C
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C
320(1+x2)23(2x2+3)+C
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D
None of these
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Solution

The correct option is B 320(1+x2)23(2x23)+C
Put 1+x2=t32x dx=3t2 dtx3(1+x2)1/3dx=x2.x(1+x2)1/3dx=32(t31)t dt=32(t4t)dt=32(t55t22)+C=320t2(2t35)+C=320(1+x2)23(2x23)+C

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