CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

[x+a2+x2]na2+x2 dx (n0)=
  1. 1n.(x+a2+x2)n+c
  2. (x+a2+x2)n+c
  3. 1n(x+a2+x2)n+c
  4. 1n+1(x+a2+x2)n+1+c


Solution

The correct option is C 1n(x+a2+x2)n+c
Put x+a2+x2=tthen [1+2x2a2+x2] dx=dt[x+a2+x2]na2+x2 dx=tn1 dt=tnn+c=1n(x+a2+x2)n+c

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...



footer-image