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Question

278e3xdx  is equal to
  1. 15e32e2
  2. 3e36e2
  3. 15e36e2
  4. 6e3+15e2


Solution

The correct option is C 15e36e2
278e3xdx
Let  x=t3   dx=3t2dt
32et3t2dt
Using integration by parts
=3t2et32tetdt 
=[3ett23et(2t)+6et]32=3e3(96+2)3e2(44+2)=15e36e2

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