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Question

sin4xcos3x dx.

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Solution

I=sin4xcos3xdx
I=sin4xcos2xcosxdx
I=sin4x(1sin2x)cosxdx
sinx=t
cosxdx=dt
I=t4(1t2)dt
I=(t4t6)dt
=t55t77+c
where t=sint
I=15sin5t17sin7t+c.

1177538_1156537_ans_52f2ed1ab4114427a1682b90c952c0ee.jpg

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