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Question

x1x21+x2dx=

A
12[sin1x2+1x4]+c
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B
12[sin1x2+1x2]+c
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C
sin1x2+1x4+c
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D
sin1x2+1x2+c
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Solution

The correct option is A 12[sin1x2+1x4]+c
x1x21+x2dx=x.(1x2)1x4dx
{Multiplying N' and D' by (1x2)1/2}
=x1x4dxx31x4dx=12[sin1(x2)+1x4]+c (By putting x2=t and 1x4=t respectively)

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