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Question

Integrate the following w.r.t:cos (4x+3)


  1. -sin(4x+3)+c

  2. sin(4x+3)+c


Solution

The correct option is A


Let u =4x+3
dudx=4

dx=du4

I=cos(4x+3)dx=cosu4du

= 14sinu+c

= 14sin(4x+3)+c

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