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Question

Integrate:
303x+1x2+9dx=$

A
ln(22)+π12
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B
ln(22)+π2
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C
ln(22)+π6
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D
None of these
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Solution

The correct option is A ln(22)+π12
303x+1x2+9dx
330xx2+9+1x2+9dx
=32[log(t)]918+13[tan1x3]03
=32[log(t)]918+13[tan1x3]03
=32[log(2)]+13[tan1330]
=32log(2)+π4×3
=log(2)32+π12
log22+π12

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