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Question

Integrate the following functions.
x2(2+3x3)3dx.


Solution

x2(2+3x3)3dx
Let 2+3x3=t9x2=dtdxdx=dt9x2
x2(2+3x3)3dx=x2t3dt9x2=191t3dt=19t3dt=19(t3+13+1)+C=19×12t2+C=118t2+C=118(2+3x3)2+C

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