Ionization energy of F -is 320 KJ - mole- The electron gain enthalpy of fluorine would beA- 160 KJ - moleB- -320 KJ - moleC- -160 KJ - moleD- 320 KJ - mole

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Electron Gain Enthalpy

Ionization en...

Question

Ionization energy of $F^{-}$ is 320KJ/mole. The electron gain enthalpy of fluorine would be

-320 KJ/mole

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-160 KJ/mole

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320 KJ/mole

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160 KJ/mole

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Solution

The correct option is A
-320 KJ/mole

I.E is opposite to electron affinity.
$F^{-} ⟶$ F + $e^{-}$ $Δ H = 320 K J / m o l e (I . E)$

$F + e^{-} ⟶$ $F^{-}$ $Δ H = - 320 K J / m o l e (I . E)$

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Ionization energy of F− is 320KJ/mole. The electron gain enthalpy of fluorine would be

The correct option is A -320 KJ/mole I.E is opposite to electron affinity. F−⟶ F + e− ΔH = 320KJ/mole(I.E) F+e−⟶ F− ΔH = −320KJ/mole(I.E)

Ionization energy of $F^{-}$ is 320KJ/mole. The electron gain enthalpy of fluorine would be

The correct option is A
-320 KJ/mole

I.E is opposite to electron affinity.
$F^{-} ⟶$ F + $e^{-}$ $Δ H = 320 K J / m o l e (I . E)$

$F + e^{-} ⟶$ $F^{-}$ $Δ H = - 320 K J / m o l e (I . E)$