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Question

IP1 and IP2 of Mg are 178 and 348kcalmole1. The energy required for the reaction MgMg2++2e is:

A
+170kcal/mol
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B
+526kcal/mol
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C
170kcal/mol
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D
526kcal/mol
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Solution

The correct option is B +526kcal/mol
MgMg++e.......IP1=+178kcalmole1
Mg+Mg2++e........IP2=+348kcalmole1
Overall: MgMg2++2e......IP=IP1+IP2
=178+348
=+526kcalmole1
IP=526kcalmole1

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