ABCD is a rectangle
∠BOC=56o
∠AOD=56o [vertically opposite ∠S]
AO=DO [diagonals]
∴∠OAD=∠ADO=x
Now △AOD is α △∴
∴∠ADO+∠OAD+56o=180
x+x+56o=180
∴x=62o∴∠ADO=62o
In the rectangle ABCD, O is any point inside the rectangle. If area(△AOD) = 30 cm2 and area(△BOC) = 60 cm2, Find the area of the rectangle ABCD. [2 MARKS]