Is the velocity of escape of a particle at rest on the surface of the earth the same as that of a particle just orbiting the earth? Explain.

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Solution

$v_{e s c a p e} = \sqrt{2 g r}$ at rest.
The body ability earth will have already a velocity $\sqrt{g r}$ .So it needs only the remaining velocity.

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Is the velocity of escape of a particle at rest on the surface of the earth the same as that of a particle just orbiting the earth? Explain.

vescape=√2gr at rest.The body ability earth will have already a velocity √gr .So it needs only the remaining velocity.

$v_{e s c a p e} = \sqrt{2 g r}$ at rest.
The body ability earth will have already a velocity $\sqrt{g r}$ .So it needs only the remaining velocity.