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Question 9 (iv)
Solve the following pairs of equation
12x1y=1,    1x+12y=8,x,y 0


Solution

Given pair of linear equations is

12x1y=1and 1x+12y=8,x,y 0
Let u=1x and v=1y

Then the above equations can be rewritten as:
u2v=1

u2v=2....(iii)

and u+v2=82u+v=16.....iv
On, multiplying Eq. (iv) by 2 and then adding with Eq. (iii), we get
4u+2v=32u2v=2                 –––––––––      5u=30
u=6

Now, put the value of u in Eq. (iv), we get
2×6+v=16
v=1612=4

 x=1u=16

and y=1v=14

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