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Question

Ka for CH3COOH is 1.8×105 and Kb for NH4OH is 1.8×105. The pH of ammonium acetate will be

A
7.005
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B
4.75
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C
7
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D
between 6 and 7
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Solution

The correct option is C 7
CH5OOONH4 is a salt of weak acid (CH3OOOH) and weak base (NH4OH)

pH=7+12(pKapKb)

pKa=logKa=log(1.8×105)=4.74

pKb=logKb=log(1.8×105)=4.74

pH=7+12(4.744.74)=7.0

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