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Question

# Kw for H2O is 9.62×10−14 at 60oC. What is pH of water at 60oC.

A
3.71
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B
6.51
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C
7.49
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D
11.31
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Solution

## The correct option is C 6.51We know that when Kw=10−14, [H3O+]=[OH−]=10−7mol/dm3The value of Kw depends on temperature. So, in the question, the value is not 10−14.SImilarly, we can use the relation for above given value of KwSo,[H3O+]=√9.62∗10−14=3.1×10−7mol/dm3 Hence,pH=−log10[H3O+]=−log10(3.1∗10−7)=7−0.49=6.51Shortcut:Remember that you cannot use log tables in your exam. So, here once you find the value of [H3O+], taking log will give you "7 - something lesser than 1" which matches with one option only i.e. B.

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