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Kw for H2O is 9.62×1014 at 60C 
The pH of water at this temperature is :
  1. 6.5
  2. 7.5
  3. 7
  4. 6


Solution

The correct option is A 6.5
We know that,
Kw=[H+] [OH]
As water is neutral and for a neutral solution:
[H+]=[OH]Kw=[H+]2Kw=9.62×1014   (Given)[H+]2=9.62×1014     [H+] =9.62×1014=31×108pH=log10[H+]pH=log10(31×108)pH=6.5 

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