CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

KMnO4+Cu2SMn2++Cu2++SO2
In above reaction, find 'n' factor of Cu2S.

Open in App
Solution

KMnO4+Cu2SMn2++Cu2++SO2
Oxidation state of Cu in Cu2S=+1
Oxidation state of Cu in Cu2+=+2
Change in oxidation state of Cu=1
Change in oxidation state of Cu2S=1×2=2
nfactor of Cu2S= Change in oxidation state of Cu2S
n factor of Cu2S=2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrode Potential and emf
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon