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Question

Kx^2+3x^2+5x+3=0 find value of k


Solution

x^2 (k+3) + 5x + 3 = 0 
Since, it is equal to zero 
D = b^2 - 4ac = 0
25 - 4 (k+3) x 3 = 0
25 = 12 (k+3)
25/12 = k+3
(25/12) - 3 = k
(25 - 36)/12 = k 
-11/12 = k  
 

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