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Question

⎜ ⎜(81)1log59+33log63409⎟ ⎟((7)2log257(125)log256)=


A
0
loader
B
1
loader
C
7+2
loader
D
5+27
loader

Solution

The correct option is B 1
We know that alogab=b

((92)log95+33 log36409)(7log725632)=(25+66409)(2566)
=625216409=1

Mathematics

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