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Question

(xbxc)(b+c).(xaxb)(a+b).(xcxa)(a+c)=?


  1.  xabc

  2. 1

  3. xa+b+c

  4. None of these


Solution

The correct option is B

1


(xbc)(b+c).(xab)(a+b).(xca)a+c=x(b2c2).x(a2b2).x(c2a2)=xb2c2+a2b2+c2a2=x0=1.

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