Question

# Length of a minute hand of a clock is 4.5 cm. Find average velocity of time of the minute hand between 6 AM. to 6.30 A.M and 6 A.M. to 6.30 P.M.

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Solution

## Given that, Time t=30 min=1800 sec Now, the length of the minute hand is almost as long as the radius of the clock The displacement is D=2×4.5 D=9cm D=0.09m Now, the velocity is v=Dt v=0.091800 v=5×10−5m/s Hence, the average velocity is 5×10−5m/s Displacement during 6:00 AM to 6:30 PM will be:D=4.5×2=9cmD=0.09 mTime taken:t=12.5 Hours.t=12.5×3600 secTherefore,Velocity will be given by:v=0.0912.5×3600=2×10−6 m/s

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