Question

Length of sides of a $△ABC$ is $AB=5cm$, $AC=3cm$ and $BC=4cm$. Then, construct the triangle formed by these three sides by following these steps. Put them in proper order.

Step 1. Draw a line segment $AB=5cm$

Step 2. Now assuming $B$ as centre draw an arc of $4cm$ intersecting the previous arc at $C$.

Step 3. Assuming $A$ a centre draw an arc of radius $3cm$

Step 4. Now join $A$ to $C$ and $B$ to $C$.

• A. $1-3-2-4$
• B. $1-4-2-3$
• C. $2-3-4-1$
• D. none of these

Answer 1

The correct option is A $1-3-2-4$

Steps of construction

Step 1. Draw a line segment $AB=cm$

Step 2. Assuming $A$ a centre draw an arc of radius $3cm$

Step 3. Now assuming $B$ as centre draw an arc of $4cm$ intersecting the previous arc at $C$.

Step 4. Now join $A$ to $C$ and $B$ to $C$.

So $1-3-2-4$ is the correct order