Length of the line segment joining the points -1-i and 2-3 i isA- -5B- 15C- 5D- 25

Since the coordinates in complex plane are (2, 3) and ( 1, 1) Hence the required distance is √((2 ( 1))^2 + (3 ( 1))^2), which is 5. Trick : We know that the d ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Modulus of a Complex Number

Length of the...

Question

Length of the line segment joining the points -1-i and 2+3i is

-5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
5

Since the coordinates in complex plane are (2, 3) and (-1,-1) Hence the required distance is $\sqrt{(2 - (- 1))^{2} + (3 - (- 1))^{2}}$ , which is 5.

Trick : We know that the distance between $z_{1}$ and $z_{2}$ is $| z_{1} - z_{2} |$
Therefore, the required length $| 2 + 3 i + 1 + i |$ = 5

Suggest Corrections

Similar questions

Q. Length of the line segment joining the points -1 -i and 2 + 3i is

Q. Length of the line segment joining the points

- 1 - i

and

2 + 3 i

on the complex plane is

Q. Length of the line segment joining the points -1 -i and 2 + 3i is

The length of line segment joining -1-i and 2+3i ?

The mid-point of the line segment joining $(2 a, 4)$ and $(- 2, 2 b)$ is $(1, 2 a + 1)$ . Then the values of $a$ and $b$ respectively are

Join BYJU'S Learning Program

Length of the line segment joining the points -1-i and 2+3i is

The correct option is C 5 Since the coordinates in complex plane are (2, 3) and (-1,-1) Hence the required distance is √(2−(−1))2+(3−(−1))2, which is 5. Trick : We know that the distance between z1 and z2 is |z1−z2| Therefore, the required length |2+3i+1+i| = 5