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Question

Let a,b,c be rational numbers and f:ZZ be a function given by
f(x)=ax2+bx+c then a+b is

A
An integer
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B
A rational number but not an integer
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C
Negative integer
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D
Nothing in particular can be said
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Solution

The correct option is A An integer
f:ZZ is given by
f(x)=ax2+bx+c xZ
Now f(0),f(1) are integers
f(1)f(0) is integer
(a+b+c)c is integer
a+b is an integer

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