Question

# Let $$A$$ be a non-empty set such that $$A \times A$$ has $$9$$ elements among which are found $$(-1, 0)$$ and $$(0, 1)$$, then

A
A={1,0}
B
A={0,1}
C
A={1,0,1}
D
A={1,1}

Solution

## The correct option is A $$A=\left\{ -1,0,1 \right\}$$Given $$A\times A$$ has $$9$$ elements $$\Rightarrow n(A)=3$$Elements of $$A\times A$$ are  $$(-1,0)$$  &  $$(0,1)$$.$$\therefore$$ $$A$$ needs to contain $$-1, 0$$ and $$1$$.$$\therefore$$ Since $$n(A)=3 \Rightarrow A=\left \{ -1,0,1 \right \}$$Mathematics

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