CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let A be the centre of the circle x2+y22x4y20=0. Suppose that the tangents at the points B(1,7) and D(4,2) on the circle meet at point C. Then the area of the quadrilateral ABCD is

A
75
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
75.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
75.00
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

Centre of the circle is A(1,2) and radius is 12+22+20=5
AB is a line segment parallel to y-axis and therefore tangent at B will be parallel to x-axis.
Let C(a,7)
Using DC=BC, we get C(16,7)
BC=15

So, area (ABC)=12×AB×BC=752
Area of quadrilateral =75

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition and Standard Forms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon