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Question

Let a function f:(0,)(0,) be defined by f(x)=11x. Then f is :

A
injective only
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B
not injective but it is surjective
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C
neither injective nor surjective
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D
both injective as well as surjective
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Solution

The correct option is A injective only
NOTE: It is a bonus question.
​​​​​​​
f(x)=11x
For x=1
f(x)=111=0
But the co-domain is (0,) which is not including 0
So f(x) is not a function.

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