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Question

Let a=log3log32. An integer k satisfying 1<2(3ak)<2 is

A
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B
1
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C
2
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D
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Solution

The correct option is B 1
a=log3log323a=log323a=log23
Now,
2(3ak)=2log232k =32k

1<2(3ak)<21<32k<213<2k<23
3>2k>32

Clearly, this inequality will hold good only for k=1.

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