Let ABC be a right triangle in which AB -6 cm - BC -8 cm and - B -90- BD is perpendicular B to AC- The circle through BCD is drawn- Construct the tangents from A to the circle-

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Circles

Let ABC be a ...

Question

Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and $∠ B = 90^{\circ}$ , BD is perpendicular B to AC. The circle through BCD is drawn. Construct the tangents from A to the circle.

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Solution

Step (1): Draw a $Δ A B C$ and perpendicular from B on AC.
Step (2): Draw a circle with BC as a diametre. This circle will pass through D
Step (3): Let O be the midpoint of BC. Join AO
Step (4): Draw a circle with AO as a diametre. This circle cuts the circle drawn in Step(2) at B and E.
Step (5): Join AE.
AE and AB are desired tangents drawn A to the circle passing thorugh B, C and D.

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Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B=90∘, BD is perpendicular B to AC. The circle through BCD is drawn. Construct the tangents from A to the circle.

Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and $∠ B = 90^{\circ}$ , BD is perpendicular B to AC. The circle through BCD is drawn. Construct the tangents from A to the circle.