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Byju's Answer
Standard VI
Mathematics
Angle
let ABCDEF be...
Question
let ABCDEF be a regular hexagon .If AD=xBC and CF=yAB,then xy
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Q.
A
B
C
D
E
F
be a regular hexagon, if
¯
¯¯¯¯¯¯¯
¯
A
D
=
x
¯
¯¯¯¯¯¯
¯
B
C
and
¯
¯¯¯¯¯¯
¯
C
F
=
y
¯
¯¯¯¯¯¯
¯
B
A
, then
(
x
+
y
)
2
+
8
=
Q.
Let
A
B
C
D
E
F
be a regular hexagon and let
→
A
B
=
→
a
,
→
B
C
=
→
b
, then
→
C
D
is equal to
Q.
A
B
C
D
E
F
be a regular hexagon, and
¯
¯¯¯¯¯¯
¯
A
B
=
¯
¯
¯
a
,
¯
¯¯¯¯¯¯
¯
B
C
=
¯
¯
b
then
¯
¯¯¯¯¯¯¯
¯
A
D
+
¯
¯¯¯¯¯¯
¯
E
B
+
¯
¯¯¯¯¯¯
¯
F
C
=
Q.
If ABCDEF is a
regular hexagon and
−
−
→
A
B
+
−
−
→
A
C
+
−
−
→
A
D
+
−
−
→
A
E
+
−
−
→
A
F
=
λ
−
−
→
A
D
, then
λ
=
Q.
If ABCDEF is a regular hexagon and if
¯
¯¯¯¯¯¯
¯
A
B
+
¯
¯¯¯¯¯¯
¯
A
C
+
¯
¯¯¯¯¯¯¯
¯
A
D
+
¯
¯¯¯¯¯¯
¯
A
E
+
¯
¯¯¯¯¯¯
¯
A
F
=
λ
¯
¯¯¯¯¯¯¯
¯
A
D
then
λ
is
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