Let B = {1 orange, 1 pineapple, 1 banana, 1 apple}

Let U = {1 orange, 1 apricot, 1 pineapple, 1 banana, 1 mango, 1 apple, 1 kiwifruit}

B’ =

{1 apricot, 1 mango, 1 kiwifruit, 1 orange, 1 pineapple, 1 apple}

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{1 apricot, 1 mango, 1 kiwifruit, 1 banana, 1 orange, 1 pineapple, 1 apple}

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{1 apricot, 1 mango, 1 kiwifruit}

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{1 orange, 1 apple, 1 banana}

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Solution

The correct option is C {1 apricot, 1 mango, 1 kiwifruit}
Given: B = {1 orange, 1 pineapple, 1 banana, 1 apple} and
U = {1 orange, 1 apricot, 1 pineapple, 1 banana, 1 mango, 1 apple, 1 kiwifruit}
B'=U-B=set of all elements of U which are not present in B.
Since, apricot, mango and kiwifruit are not the elements of set B, they are elements of set B’.

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Let B = {1 orange, 1 pineapple, 1 banana, 1 apple} Let U = {1 orange, 1 apricot, 1 pineapple, 1 banana, 1 mango, 1 apple, 1 kiwifruit} B’ =

Let B = {1 orange, 1 pineapple, 1 banana, 1 apple}

Let U = {1 orange, 1 apricot, 1 pineapple, 1 banana, 1 mango, 1 apple, 1 kiwifruit}

B’ =