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Question

Let (x,y,z) be points with integer coordinates
satisfying the system of homogeneous equations :
3xyz=0...(i)
3x+z=0...(ii)
3x+2y+z=0...(iii)
Then, the number of such points for which x2+y2+z2100, is

A
6
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B
7
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C
49
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D
none of these
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Solution

The correct option is B 7
3xyz=0...(1)
3x+z=0...(2)
3x+2y+z=0...(3)
adding (1) and (2) gives y=0
but from (2) 3x=z
solution for the given set of equations is (x,y,z)=(t,0,3t) where t is an integer.
For, x2+y2+z2100
10t2100
t210
possible values of t are 3,2,1,0,1,2,3
i.e 7 possible solutions.
Hence, option B.

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