Question
Let f(x)=1−tanx4x−π, x≠π4 , then limx→π4f(x)=
Let f(x)=1−tanx4x−π, x≠π4 , then limx→π4f(x)=
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Solution
The correct option is B −12
f(x)=1−tanx4x−π
⇒limx→π4f(x)=limx→π4(1−tanx4x−π)Applying L−Hospital′s rule we get,
=limx→π4(−sec2x4)=−sec2π44=−24
⇒limx→π4f(x)=−12
f(x)=1−tanx4x−π
⇒limx→π4f(x)=limx→π4(1−tanx4x−π)
Applying L−Hospital′s rule we get,
=limx→π4(−sec2x4)=−sec2π44=−24
⇒limx→π4f(x)=−12
=limx→π4(−sec2x4)=−sec2π44=−24
⇒limx→π4f(x)=−12
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