Let N - 45-45-45-45-35-35-35-65-65-65-65-65-65-25-25- then the value of log 2N-

The correct option is C 12 N=4× 4^53× 3^5×6×6^52×2^5=4^6×6^63^6×2^6 = ( 4×63×2 )^6=4^6 ∴ log_2N=log_24^6=6×log_24 =6×2=12 ...

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Byju's Answer

Standard XII

Mathematics

Integration by Partial Fractions

Let N = 45+...

Question

Let $N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ , then the value of ${log}_{2} N =$

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Solution

The correct option is C $12$
$N = \frac{4 \times 4^{5}}{3 \times 3^{5}} \times \frac{6 \times 6^{5}}{2 \times 2^{5}} = \frac{4^{6} \times 6^{6}}{3^{6} \times 2^{6}}$
$= {(\frac{4 \times 6}{3 \times 2})}^{6} = 4^{6}$
$∴ {log}_{2} N = {log}_{2} 4^{6} = 6 \times {log}_{2} 4$
$= 6 \times 2 = 12$

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Similar questions

Let N = $\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} \cdot \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ then the value of ${log}_{2} N$ =

Q. If

\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{2^{5} + 2^{5}} \times \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{3^{5} + 3^{5} + 3^{5}} = 8^{n}

, then n is:

Class intervals / Frequency

15-25. 6

25-35. 11

35-45 . 7

45-55. 4

55-65. 4

65-75. 2

75-85 . 1

Find the measure of $∠ D C E$ and hence $∠$ DEC

Q. Find the mean, using direct method:

Class	25-35	35-45	45-55	55-65	65-75
Frequency	6	10	8	12	4

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Let N=45+45+45+4535+35+35.65+65+65+65+65+6525+25, then the value of log2N=

The correct option is C 12N=4×453×35×6×652×25=46×6636×26=(4×63×2)6=46∴log2N=log246=6×log24=6×2=12

Let $N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ , then the value of ${log}_{2} N =$

The correct option is C $12$
$N = \frac{4 \times 4^{5}}{3 \times 3^{5}} \times \frac{6 \times 6^{5}}{2 \times 2^{5}} = \frac{4^{6} \times 6^{6}}{3^{6} \times 2^{6}}$
$= {(\frac{4 \times 6}{3 \times 2})}^{6} = 4^{6}$
$∴ {log}_{2} N = {log}_{2} 4^{6} = 6 \times {log}_{2} 4$
$= 6 \times 2 = 12$