Let electronegativity, ionisation energy and electron affinity be represented as EN, IP and EA respectively. Which one of the following equation is correct according to Mulliken?

E N = I P \times E A

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E N = I P / E A

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E N = (I P + E A) / 2

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E N = I P + E A

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Solution

The correct option is D $E N = (I P + E A) / 2$
Mulliken has defined electronegativity as the average of Ionization Potential and Electronegativity.
Therefore, Electronegativity (EN) can be expressed as the average of the ionization energy (IE) and the electron affinity (EA) of an atom.

Thus EN $= \frac{(I P + E A)}{2}$
Hence, the correct answer is option $C$ .

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