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Question

Let f:[0,3][0,π3+loge2] defined f(x)=loge x2+1+tan1x then f(x) is


A

one – one and onto

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B

one – one but not onto

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C

onto but not one – one

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D

neither one – one nor onto

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Solution

The correct option is A

one – one and onto


f(x)=x+1x2+1 f(x) is increasing in[0,3], So it is one one function.
and since range is equal to codomain, it is onto.


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