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Question

Let f be a function satisfying the functional equation f(x)+2f(2x+1x2)=3x,x2; then, the value of f(7) is

A
5
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B
-5
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C
1
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D
-1
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Solution

The correct option is D -1
Replace x2x+1x2
f(2x+1x2)+2f(x)=3(2x+1x2)(1)
Given f(x)+2f(2x+1x2)=3x(2)
Solving (1) & (2)
f(x)=x2+6x+2x2
f(7)=44495=1

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