Let f,g:R→R be defined, respectively by f(x) = x + 1, g(x) = 2x - 3. Find f + g, f - g and fg.
Here f(x) = x + 1 and g(x) = 2x - 3.
Now (f + g)(x) = f(x) + g(x)
= x + 1 + 2x - 3 = 3x - 2
(f - g)(x) = f(x) - g(x) = x + 1 - (2x - 3)
= x + 1 - 2x + 3 = - x + 4
(f)(g)(x)=f(x)g(x)=x+12x−3,x≠32