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Question

Let f(x)=x2+x6. For what values of "t" does f(t5)=0?

A
3 and 2
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B
2 and 3
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C
5
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D
2 and 7
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Solution

The correct option is C 2 and 7
f(x)=x2+x6
f(t)=t2+t6
f(t5)=(t5)2+(t5)6
f(t5)=t29t+14

f(t5)=0
t29t+14=0
t27t2t14=0
t(t7)2(t7)=0
(t7)(t2)=0
t=7 or t=2

So, the answer is option (D)


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