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Question

Let f:RR be defined by f(x)=2x+6 which is a bijective mapping then f1(x) is given by 
  1. x23
  2. 2x+6
  3. x3
  4. 6x+2


Solution

The correct option is A x23
f(x)=2x+6
x=f(x)62
f1(f(x))=f(x)62
f1(x)=x62=x23

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